发布时间:2010-08-02 15:43:01
文章类别:宏包使用
原文地址:http://blog.sina.com.cn/s/blog_5e16f1770100ktrn.html
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常见数学公式问题集下载
示例如下图:
示例代码:
\usepackage{amsmath}
\usepackage{cancel}
\begin{align*}
& \sum_{k=1}^n [1/k - 1/(k+1)] \\
&= [1-1/2]+[1/2-1/3]+\cdots+[1/n-1/(n+1)] \\
&= [1-\cancel{1/2}]+[\cancel{1/2}-\cancel{1/3}]+[\cancel{1/3}-\cancel{1/4}]\cdots+[\cancel{1/n}-1/(n+1)]
&= [1-\bcancel{1/2}]+[\bcancel{1/2}-\bcancel{1/3}]+[\bcancel{1/3}-\bcancel{1/4}]\cdots+[\bcancel{1/n}-1/(n+1)]
&= [1-\xcancel{1/2}]+[\xcancel{1/2}-\xcancel{1/3}]+[\xcancel{1/3}-\xcancel{1/4}]\cdots+[\xcancel{1/n}-1/(n+1)]
&=1-1/(n+1)
\end{align*}
2
$$
\bcancel{a+b}
$$
3
$$
a+\xcancel{b-b}
$$
4
$$
\cancelto{1234}{123+1234-123}
$$
$$
\cancelto{\text{Is it right?}}{\frac 12 +\frac 13 = \frac 25}
$$
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