发布时间:2009-12-06 11:46:41
文章类别:数学公式
原文地址:http://blog.sina.com.cn/s/blog_5e16f1770100gb05.html
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常见数学公式问题集下载
Inline and Displayed
Formulas
$x=\frac{1+y}{1+2z^2}$
(inline) |
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$$x=\frac{1+y}{1+2z^2}$$
(displayed) |
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$\int_0^\infty e^{-x^2} dx=\frac{\sqrt{\pi}}{2}$
(inline) |
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$$\int_0^\infty e^{-x^2} dx=\frac{\sqrt{\pi}}{2}$$
(displayed) |
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$\displaystyle \int_0^\infty e^{-x^2} dx$
(inline) |
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$$
\frac{1}{\displaystyle 1+
\frac{1}{\displaystyle 2+
\frac{1}{\displaystyle 3+x}}} +
\frac{1}{1+\frac{1}{2+\frac{1}{3+x}}}
$$
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$\sqrt{2} \sin x$, $\sqrt{2}\,\sin x$
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$\int \!\! \int f(x,y)\,\mathrm{d}x\mathrm{d}y$
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$$
\mathop{\int \!\!\! \int}_{\mathbf{x} \in \mathbf{R}^2}
\! \langle \mathbf{x},\mathbf{y}\rangle
\,d\mathbf{x}
$$
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$$ x_1 = a+b \mbox{ and } x_2=a-b $$
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$$ x_1 = a+b ~~\mbox{and}~~ x_2=a-b $$
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\begin{eqnarray}
y &=& x^4 + 4 \nonumber \\
&=& (x^2+2)^2 -4x^2 \nonumber \\
&\le&(x^2+2)^2
\end{eqnarray}
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\begin{eqnarray*}
e^x &\approx& 1+x+x^2/2! + \\
&& {}+x^3/3! + x^4/4! + \\
&& + x^5/5!
\end{eqnarray*}
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\begin{eqnarray*}
\lefteqn{w+x+y+z = }\\
&& a+b+c+d+e+\\
&& {}+f+g+h+i
\end{eqnarray*}
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\begin{eqnarray*}
x&=&\sin \alpha = \cos \beta\\
&=&\cos(\pi-\alpha) = \sin(\pi-\beta)
\end{eqnarray*}
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{\setlength\arraycolsep{0.1em}
\begin{eqnarray*}
x&=&\sin \alpha = \cos \beta\\
&=&\cos(\pi-\alpha) = \sin(\pi-\beta)
\end{eqnarray*}
}
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$$\setlength\arraycolsep{0.1em}
\begin{array}{rclcl}
x&=&\sin \alpha &=& \cos \beta\\
&=&\cos(\pi-\alpha) &=& \sin(\pi-\beta)
\end{array}
$$
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\begin{equation} x=y+3 \label{eq:xdef}
\end{equation}
In equation (\ref{eq:xdef}) we saw $\dots$
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\usepackage{leqno}
...
\begin{equation} x=y+3 \label{eq:xdef}
\end{equation}
In equation (\ref{eq:xdef}) we saw $\dots$
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\begin{equation}
\begin{array}{l}
\displaystyle \int 1 = x + C\\
\displaystyle \int x = \frac{x^2}{2} + C \\
\displaystyle \int x^2 = \frac{x^3}{3} + C
\end{array}
\label{eq:xdef}
\end{equation}
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\begin{eqnarray}
&& \int 1 = x + C \nonumber\\
&& \int x = \frac{x^2}{2} + C \nonumber\\
&& \int x^2 = \frac{x^3}{3} + C \label{eq:xdef}
\end{eqnarray}
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$\left] 0,1
\right[
+ \lceil x \rfloor - \langle x,y\rangle$
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$$
{n+1\choose k} = {n\choose k} + {n \choose k-1}
$$
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$$
|x| = \left\{ \begin{array}{rl}
-x &\mbox{ if $x<0$} \\
x &\mbox{ otherwise}
\end{array} \right.
$$
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$$
F(x,y)=0 ~~\mbox{and}~~
\left| \begin{array}{ccc}
F''_{xx} & F''_{xy} & F'_x \\
F''_{yx} & F''_{yy} & F'_y \\
F'_x & F'_y & 0
\end{array}\right| = 0
$$
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$$
\underbrace{n(n-1)(n-2)\dots(n-m+1)}_
{\mbox{total of $m$ factors}}
$$
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Accents in text
mode:
gar\c con \'\i{} i
t\`o\'s\.g\^o na\"\i ve na\"ive
Ha\v cek
\r Angstr\"om
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Accents in math
mode:
$\hat{x}$, $\check{x}$, $\tilde{a}$,
$\bar{\ell}$, $\dot{y}$, $\ddot{y}$,
$\vec{z_1}$, $\vec{z}_1$
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Wide accents, under and
overline:
$\hat{T} = \widehat{T}$,
$\bar{T} = \overline{T}$, $\widetilde{xyz}$,
$\overbrace{a+\underbrace{b+c}+d}$
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$$
\overline{\overline{a}^2+\underline{xy}
+\overline{\overline{z}}}
$$
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Sub and superscripts to
braces:
$$
\underbrace{a+\overbrace{b+\cdots}^{{}=t}+z}
_{\mathrm{total}} ~~
a+{\overbrace{b+\cdots}}^{126}+z
$$
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